Question

The mass M shown in the figure oscillates in simple harmonic motion with amplitude A. The amplitude of the point P is

Answer 1

Answer:

amplitude of the point P = [k2/(k1+k2)]*A

Explanation:

suppose we apply a force F to the mass M,

then,F=k1x1

     F=k2x2            [where x1 and x2 are the displacements of two strings]

If total distance is taken as A,then,

A= x1+x2

   = F[1/k1 + 1/k2]

  =[k1k2/(k1+k2)]

so amplitude of point x1= F/x1 =[k2/(k1+k2)]*A

so amplitude of point P,x1=[k2/(k1+k2)]*A

hope it help u