The mass no of iron nucleus is 56 the nuclear density is
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✴Given mass of iron nucleus is 55.85u and A=56.
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✴Given mass of iron nucleus is 55.85u and A=56.
Hope it helps you ✴(^^)✴
Thanks ✴O:-)✴
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heyy bro ur answer...........
according to rutherford's relationsradius of nucleus = ro×A13 ro = constant = 1.2×10−15 m thereforer = 1.2×10−15 ×56−−√3r = 4.59 ×10−15 malso,1u = 1.67×10−27 kg55.85 u = 9.327 ×10−26 kg = mass of nucleus of iron atomnuclear density = mass of nucleus of iron atomvolume of nucleus nuclear density = 9.327 ×10−26 kg43π×r3 =9.327 ×10−26 kg43π×(4.59 ×10−15 )3nuclear density = 4.851×1018 kg/m^3
i hope it will help u......@kundan
according to rutherford's relationsradius of nucleus = ro×A13 ro = constant = 1.2×10−15 m thereforer = 1.2×10−15 ×56−−√3r = 4.59 ×10−15 malso,1u = 1.67×10−27 kg55.85 u = 9.327 ×10−26 kg = mass of nucleus of iron atomnuclear density = mass of nucleus of iron atomvolume of nucleus nuclear density = 9.327 ×10−26 kg43π×r3 =9.327 ×10−26 kg43π×(4.59 ×10−15 )3nuclear density = 4.851×1018 kg/m^3
i hope it will help u......@kundan
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