Question

the mass of 10 cm3 of silver is 103gm find the density in kg/m3​

Answer 1

Answer:

1.03

Explanation:

volume =10 cm^3

mass = 103 g\cm^3

v=10\100=0.10m^3 as 1m=100cm

mass=103\1000=0.103 as 1g cm =1000kg m

density = mass\volume

density=0.10\0.103=1.03

1.03kgcm^3

Answer 2

Answer:

The density of the silver will be equal to 10.3×10³kgm⁻³.

Explanation:

Given: the mass of the silver, $m=103g=0.103Kg$

The volume occupies by the silver, $V=10cm^{3}$

$V=10(10^{-2}m)^{3}$

$V=10^{-5}m^{3}$

Density is defined as mass per unit volume. Density increases with increase in mass and decreases with increase the volume.

$Density=\frac{Mass}{Volume}$                                           .....................(1)

Put the value of m=0.103kg and V=10⁻⁵m³ in equation(1);

$Density=\frac{0.103kg}{10^{-5}m^{3}}$

$Density=0.103*10^{5}kgm^{-3}$

$Density=10.3*10^{3}kgm^{-3}$

Therefore, the density  of silver is equal to 10.3×10³kg/m³.