Chemistry, asked by sarathnv415, 7 months ago

The mass of 1mole mg 12 if do how many grams of mg are there in 36 grams mg

Answers

Answered by krish4711
0

Answer:

Q. No. 1 Which of the following contains equal to those in 12g Mg? (At. Wt. Mg = 24)

Option 1 12 gm C

Option 2 7 gm N2

Option 3 32 gm O2

Option 4 None of these

Correct Answer 2

Explanation 12 1 Moles of Mg = = 24 2

1 Atoms = N

2

  A

7 1 Moles of N = =

28 4 2

1 N No of atoms = N 2=

4 2

   A

A

Q. No. 2

If moles of oxygen combine with Al to form Al O ,the weight of Al used in 1

1 he

2

t 2 3

reaction is (Al = 27)

Option 1 27 g

Option 2 54 g

Option 3 40.5 g

Option 4 81 g

Correct Answer 2

Explanation 3

2Al+ O Al O

2

2 2 3 

3

2 mole mole

2

For mole of O , moles of Al required is 2

2

e

3 mol 2

  at = 2 27 = 54gm

Q. No. 3 Which has the highest mass?

Option 1 50 g of iron

Option 2 5 moles of N2

Option 3 0.1 mol atom of Ag

Option 4 1023 atoms of carbon

Correct Answer 2

Explanation 50 gm Fe

5 moles N = 5 28 = 140gm 2 

1 mole Ag = 0.1 108 = 10.8 gm 

10 1 10 atomof C = moles = moles

6.022 10  6.022

23

23

23

1

= 12= 2 gm

6.022

Q. No. 4 The number of atoms present in 0.5 mole of nitrogen is same as the atoms in

Option 1 12 g of C

Option 2 64 g of S

Option 3 8 g of O

Option 4 48 g of Mg

Correct Answer 1

Explanation 0.5 mole N contains 0.5 N molec e  ul s 2 A

= 0.5 N 2 = N atom   A A

This is same for 12 gm of C

Q. No. 5 Which of the following weighs the least?

Option 1 2 g atom of N (at. wt. of N = 14)

Option 2 3 10  atoms of C (at. wt of C = 12) 23

Option 3 1 mole of S (at. wt. of S = 32)

Option 4 7 g silver (at. wt. of Ag = 108)

Correct Answer 2

Explanation 2 gm atom of N 28 gm 

3 10 1 3 10 atomof C = = moles

6 10 2

23

23

23

1

= 12=6gm

2

1 mole of S = 32 gm

7 gm Ag

Q. No. 6 If NA is Avogadro’s number then number of valence electrons in 4.2 g of nitride ions

(N3–

) is

Option 1 2.4 NA Option 2 4.2 NA Option 3 1.6 NA Option 4 3.2 NA Correct Answer 1

Explanation 4.2 Moles = = 0.3

14

0.3 mole contains 0.3 NA ions

One ion has 8 valence electron : total valence electron = 0.3NA A  8 = 2.4 N

Q. No. 7 Hemoglobin contains 0.33 % of iron by weight. The molecular weight of hemoglobin is

approximately 67200. The number of iron atoms (at. wt. of Fe = 56) present in one

molecule of hemoglobin is

Option 1 6

Option 2 1

Option 3 4

Option 4 2

Correct Answer 3

Explanation 100 gm of Haemoglobin contains 0.33 gm of iron. Let there are x atoms of iron present

in one molecule.

100 1 Moles of Haemoglobin= = 67200 672

0.33 Moles of Fe = = 4

672 56

x

 x

Q. No. 8 The number of molecules in 4.25 g of ammonia is about

Option 1 1.0 10 

23

Option 2 1.5 10 

23

Option 3 2.0 10 

23

Option 4 2.5 10 

23

Correct Answer 2

Explanation 4.25 Moles = = 0.25

17

   No. of molecules = 0.25 6.023 1023

= 1.5 10 

23

Q. No. 9 If 20% nitrogen is present in a compound, its minimum molecular weight can be

Option 1 144

Option 2 28

Option 3 100

Option 4 70

Correct Answer 4

Explanation For minimum molecular weight 1 mole of compound must contain 1 mole of atom.

Moles of compound = Moles of atom

100 20 = M= 70

M 14

 

Q. No. 10 The weight of molecule of the compound C60H122 is

Option 1 1.4 10 g 

-21

Option 2 1.09 10 g 

-21

Option 3 5.025 10 g 

23

Option 4 16.023 10 g 

23

Correct Answer 1

Explanation (6 wt

0

o

1

f on 2+12 e molecu 2 1) = gm

6. 0

l

022

e

1

 

23

=1.4 10 gm

HOPE THIS HELPS U.

PLZ MARK AS BRAINLYEST.

Similar questions