The mass of 2.43 litres of ch4 at 1.5 atoms and 27 degree celsius is
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Explanation:
Given, p= 16 atm, v=9L, n=m/M ,where M is molecular weight of Methane i.e, 16, R= 0.0821 T = 27+273=300
Ideal gas equation PV=m/M RT
16x9= m/16 x0.0821x300=96grams
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