Question

the mass of 2.43L of CH4 at 1.5 ATM and 27°C​

Answer 1

Answer:

apply pv =nrt

Explanation:

as 1.5 x 2.43 = n x 8.31 x    300[ 27+273 change to kelvin ]

so the answer is 3.645= n 2493

so n =0.0012 moles

as 1mole of ch4 is 16 so the value of 0.0012 moles is 0.0198

so please mark as brainliest

Answer 2

Answer:2.4 g

Explanation:

P = 1.5 atm

V = 2.43L

T = 273 + 27 = 300 K

R = 0.0821

n = Given mass/Molecular mass

= x/16. (Let the given mass be x)

PV = nRT

1.5 x 2.43 = x/16 × 0.0821 × 300

3.65 × 16 = x × 24.6

x = (3.65 ×16)/24.6

x = 2.4 g

Hope it helps...