The mass of 3.01 x 10^23 molecule of a triatomic gas (A³)is 12 g. Calculate the no atoms in 8 gram of gas
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12g contain=3.01×10^23
1g. =3.01×10^23÷12
8g. =3.01×10^23÷12×8=2×10^23
1g. =3.01×10^23÷12
8g. =3.01×10^23÷12×8=2×10^23
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2
Answer is 2*10^23
Hope it helps
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