Question

The mass of 3.0115 *10^23 molecules of chlorine is

Answer 1

35.5 is the correct answer

Answer 2

The mass of  $3.0115\times 10^{23}$ molecules of chlorine is 35.5 g

Explanation:

According to Avogadro's law, 1 mole of every substance contains Avogadro number of particles (atoms, molecules or ions) i.e. $6.023\times 10^{23}$ particles.

Thus as we know:

1 mole molecule of chlorine $(Cl_2)$ contains $6.023\times 10^{23}$ molecules of water.

$6.023\times 10^{23}$ molecules are present in = 1 mole

$3.0115\times 10^{23}$ molecules will be present in =$\frac{1}{6.023\times 10^{23}}\times 3.0115\times 10^{23}=0.5$ moles

1 mole of chlorine  $(Cl_2)$ weighs = 71 g

0.5 moles of chlorine  $(Cl_2)$ weigh =$\frac{71}{1}\times 0.5=35.5g$

The mass is 35.5 g

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