Question

The mass of 350 cm of a diatomic gas at 273 K at 2 atmospheres pressure is one gram.
Calculate the mass of one atom of the gas.​

Answer 1

5.3×10

−23

g

n=

RT

PV

=

0.082×273

2×0.35

≈0.031mol

0.031 mol weight 1g

0.031×6022×10

23

atoms= 1g

=

0.031×6.022

1

×10

−23

=5.3×10

−23

g