Question

The mass of 5.6L carbon dioxide at STP is

Answer 1

Explanation:

Using the ideal gas equation, we can solve for the number of moles:

PV=nRT

where:
P=pressure
V=volume
n=moles
R=universal constant (8.314kPa⋅Lmol⋅K)
T=temperature (Kelvin)

Recall that at STP conditions:

P=101.325 kPa
T=273.15 K

To solve for the number of moles of carbon dioxide gas, substitute your known values into the ideal gas equation:

PV=nRT

n=PVRT

n=(101.325kPa)(5.6L)(8.314kPa⋅Lmol⋅K)(273.15K)

n=(101.325kPa)(5.6L)(8.314kPa⋅Lmol⋅K)(273.15K)

n=0.2498580892 mol

n=0.25 mol (rounded to 2 significant figures)

∴, there are 0.25 mol in 5.6 L of CO2(g) at STP conditions.

hope it helps you

Answer 2

If your mole concept is being clear .then I should have been solve this.it was a kinda simple.