Question

The mass of 5.6l of a certain gas at S.T.P is 12g. What is the relative molecular mass of the gas?

Answer 1

1 mole = 22.4L

Therefore 5.6L = 5.6÷ 22.4 =0.25 mol

Then we have to divide

12 (given mass) by the result 0.25

12÷0.25 = 48 g {ANS}.

Answer 2

Given:

Mass of gas = 5.6 L

Weight = 12g

To find:

Relative molecular mass of the gas = ?

Calculation:

The weight of 22.4 L of gas at STP = Gram molecular mass

As per the given statement in the question

Weight of 5.6 L of gas at STP = 12g

∴ Weight of 22.4 L of gas at STP = $\frac{12}{5.6}\times 22.4$ = 2.142× 22.4 = 48g.

Conclusion:

The relative molecular mass of the gas is found to be 48g.

Learn more about such concept

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(c). (NH4)2SO4

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(e). Potassium chlorate

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