The mass of 56 cc of CO at STP (C=12, O=16)
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Molar mass of CO = 12 + 16 = 28 g/mol. Therefore, 22.4 L ( 22400 cm3) is the volume of 28g CO at STP. 56 cm3 will be the volume of (28/22400) x 56 = 0.07 g of CO at STP.
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