Question

The mass of 6.023 ×10^22 molecules of a gas is 6.4 g ,the vapour density of the gas is

Answer 1

Answer:

12.8

Explanation:

It's given that the molecules are 6.023* 10^22 or Na

That means;

No of moles = 1 = mass given/ atomic mass

so atomic mass will be 6.4

vapor density = Atomic mass*2

                       = 6.4*2 = 12.8