Question

The mass of 70% H2SO4 required for neutralization of 1 mole of NAOH is

Answer 1

If we take into context the neutralization reaction

Then:

h2so4 + 2NaOH ---> Na2SO4 + 2H2O

0.5 Moles of h2so4 are needed

And we know that the molar mass of h2so4 = 98g

0.5 moles mass of h2so4 would be = 98*0.5=49g

70 g h2so4 is there in 100 g solution (70% h2so4)

Thus 49g is there in 70g of solution

(49x100)/70=70g

Ans = 70 g