The mass of 80% pure H2SO4 required to completely neutralise 60g of Na OH is
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2 Na OH + H2 SO4 => Na2 SO4 + 2 H2 O
=>So two moles of Na OH ie., 2 * 58.44 gms reacts with one mole ie., 98 gm of Sulfuric acid.
=>60 gm of hydroxide reacts with mass m of sulfuric acid
=> m = 60 * 98 / 116.88 gms
The mass of 80% pure acid is then: 100* m / 80
#Be Brainly☺️
=>So two moles of Na OH ie., 2 * 58.44 gms reacts with one mole ie., 98 gm of Sulfuric acid.
=>60 gm of hydroxide reacts with mass m of sulfuric acid
=> m = 60 * 98 / 116.88 gms
The mass of 80% pure acid is then: 100* m / 80
#Be Brainly☺️
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