the mass of a 10 kg is suspended from a string the other end of which is held in hand find the tension in the string when the hand is moving with a uniform acceleration of 2 metre per second square given small G is equal to 10 M per second square
Answers
Answer:
m=10
a=2 m/s^2
so, T=(ma)+(mg)
= (10×10)+(10×2)
= 100+20
= 120N
Explanation:
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Answer:
The tension in the string when the hand is moving with a uniform acceleration of 2m/s² is equal to 120N.
Explanation:
We have given, a mass attached with a string held in hand and hand is moving upward with uniform acceleration.
The mass of body attached with string, m = 10kg
Acceleration with which hand is moving, a = 2m/s²
We know that the acceleration due the gravity, g = 10ms⁻²
As the hand moves upward, the tension in the string is given by:
T = ma + mg
T = m(a + g)
T = (10kg)(2m/s² + 10ms⁻²)
T = 10×(12)kgms⁻²
T = 120N
Therefore, the tension in the string will be equal to 120N when the hand will move upward with acceleration 2m/s².
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