# the mass of a beaker is found to be (35.6+- 0.2)gram when empty, and (46.4+-0.2)gram when filled partially with a liquid. find the mass of the liquid with proper uncertainty.

## Answers

**Answer:**

(46.4-35.6)+-(0.2+0.2)

### =10.8+-0.4.

**Answer:**

The mass of the liquid with proper uncertainty is** (10.8±0.4)gm**

**Explanation:**

**Given : **

- The mass of a beaker is found to be (35.6+- 0.2)gram
- The mass f a vessel is filled partially filled with liquid (46.4+-0.2)gram.

**To find:** The mass of the liquid with proper uncertainty.

**Solution:**

**Given that,**

The mass of a beaker is found to be (35.6+- 0.2)gram

Mass of empty vessel

⇒ M1 = (35.6±0.2)gm

Mass of vessel filled with water

⇒ M2=(46.4±0.2)gm

We know that the liquid's mass is defined by the ratio of its volume in an empty and filled beaker.

Mass of water

⇒ W=M2−M1

⇒ W=46.4−35.6

=10.8gm

We can now use the relative error formula to find the error in this value.

Error in W

⇒ ΔW=±(|ΔM1|+|ΔM2|)

ΔW=±(|0.2|+|0.2|)

=±(0.4)gm

(10.8±0.4)gm

As a result the mass of liquid is (10.8±0.4)gm

**Final answer:**

The mass of the liquid with proper uncertainty is** (10.8±0.4)gm**

**#SPJ2**