the mass of a beaker is found to be (35.6+- 0.2)gram when empty, and (46.4+-0.2)gram when filled partially with a liquid. find the mass of the liquid with proper uncertainty.
Answers
Answer:
(46.4-35.6)+-(0.2+0.2)
=10.8+-0.4.
Answer:
The mass of the liquid with proper uncertainty is (10.8±0.4)gm
Explanation:
Given :
- The mass of a beaker is found to be (35.6+- 0.2)gram
- The mass f a vessel is filled partially filled with liquid (46.4+-0.2)gram.
To find: The mass of the liquid with proper uncertainty.
Solution:
Given that,
The mass of a beaker is found to be (35.6+- 0.2)gram
Mass of empty vessel
⇒ M1 = (35.6±0.2)gm
Mass of vessel filled with water
⇒ M2=(46.4±0.2)gm
We know that the liquid's mass is defined by the ratio of its volume in an empty and filled beaker.
Mass of water
⇒ W=M2−M1
⇒ W=46.4−35.6
=10.8gm
We can now use the relative error formula to find the error in this value.
Error in W
⇒ ΔW=±(|ΔM1|+|ΔM2|)
ΔW=±(|0.2|+|0.2|)
=±(0.4)gm
(10.8±0.4)gm
As a result the mass of liquid is (10.8±0.4)gm
Final answer:
The mass of the liquid with proper uncertainty is (10.8±0.4)gm
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