Question

The mass of a body is 70 kg. When completely immersed in water, it displaces 200 cm3 (2000 cm cube) of water. What is the relative density of the material of the body.

Answer 1

$\textbf{\huge{ANSWER:}}$

Given:
Mass = 70 kg
Weight of water displaced = 2000${cm}^{3}$

Weight = 2000${cm}^{3}$

=》 2×${10}^{-3} {cm}^{3}$

Density of the substance = $\frac{70}{2 \times {10}^{-3}}$

=》 $35 \times{10}^{3}$

Relative Density = $\frac{Density\:of\:substance}{Density\:of\:water}$

=》 $\frac{35 \times{10}^{3}}{{10}^{3}}$

=》 $\textbf{35}$

Hope it Helps!! :)

Answer 2

$\huge\textbf{Answer :}$

Mass = 70 kg

Weight of water displaced = 2000 cm³

Means; Weight = 2000 cm³

$2×{10}^{-3}$ ${cm}^{3}$

Density of the substance = $\dfrac{70}{2 \times {10}^{-3}}$

= $35\:\times\:{10}^{3}$

Relative Density = 

$\dfrac{Density\:of\:substance}{Density\:of\:water}$

= $\dfrac{35 \times{10}^{3}}{{10}^{3}}$

Relative Density of material of the object is $\textbf{35}$