Question

The mass of a boy is 20kg and the area of the sole of his foot is 0.01m².If g=10m/s, calculate the pressure exerted on the floor when he is standing on his a)both feet,b)one foot.

Answer 1

Pressure exerted. = Thrust/Area

For one foot,

Force exerted or thrust = ma = (20*10)N= 200N

Area = 0.01m^2

Pressure = 200/0.01= 20000Pa

For both foot, Area = 2*0.01m^2=0.02m^2

Pressure= 200/0.02 = 10000Pa