Question

the mass of A bullet is 250gm and it recoils with the speed of 50m/s what is momentum of the canon?​

Answer 1

Answer:

Let the recoil velocity of gun be V.

Mass of gun M

gun

=5.0 kg

Mass of bullet M

bullet

=0.01 kg

Velocity of bullet V

bullet

=250 m/s

Initial momentum of the system P

i

=0

Applying the conservation of linear momentum : P

f

=P

i

Or M

gun

V+M

bullet

V

bullet

=0

Or 5×V+0.01×250=0

⟹ V=−0.5 m/s

Answer 2

Answer:

The momentum of the canon is 12.5 kg • m/s

Step by Step Explanation:

Given :

$\textsf{Mass of the bullet = 250 gm}$

$\textsf{Recoils speed of the bullet = 50 m/s}$

To find :

$\textsf{Momentum of the canon}$

Taken :

To find the momentum use this formula -:

$\boxed{\sf{p=mv}}$

Where,

p = Momentum

m = Mass

v = Velocity

Solution :

$:\implies\sf{p=mv}$

$:\implies\sf{p=250gm\times50m/s}$

$:\implies\sf{p=12500\:gm.m/s}$

Convert it in kg•m/s

$:\implies\sf{p=12.5\:kg.m/s}$

So , the momentum of the canon is 12.5 kg•m/s .