The mass of a certain object is 6kg. What is the force that could have acted on it,if it's velocity increased from 5ms-1 to 13ms-1 during 5s
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6
F=m×a=m×(v-u) /t=6×[13-5]/8=6×8/8=6N
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F= m (v-u) /t
M= 6 kg
V =13m/s
U =5m/s
T=5s
So,
Force=((6) X (13-5))/5=48/5 =9.6N
M= 6 kg
V =13m/s
U =5m/s
T=5s
So,
Force=((6) X (13-5))/5=48/5 =9.6N
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