Question

The mass of a cricket ball is 0.21 kg. If the order of uncertainty in position is 100 pm then uncertainty in its velocity will be :​

Answer 1

Answer:

by heisenberg's uncertainity principle

Δx . Δp ≥ h/ 4π

here Δ x =  uncertainity in position

        Δ p = uncertainity in momentum = mΔv

m = mass of object

v = velocity

the eq

   Δx . mΔv = h/4π

Δv= h/ (4π m Δx)

    = (6.632 *10⁻³⁴) / ( 4* 3.14* 0.21* 100 *10⁻¹²)

    = 2.514 * 10⁻²⁴ m/s

hope it helps

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