The mass of a cyclist together with bicycle is 90 kg. Calculate the work done by cyclist if the speed increases from 6km/h to 12km/h.
Answers
Answered by
3
Let the work done by the cyclists be W
given mass m=90kg
initial velocity u=6km/h=6000/60x60m/s=1.667m/s
final velocity V =12km/h=12000/60x60 m/s=3.334
using v^2=u^2+2aS
2aS=(3.334)^2-(1.667)^2
aS =11.116-2.779/2
aS=8.337/2
aS =4.1685 m^2/sec.square
therefore,
W=FxDisplacement
W=ma x S. [F=ma,where a=acceleration ]
W=m x(aS)
W=90x4,1685
W=375.165 joules
Hence work done to increase the speed of bicycle by the bicyclists =375.165 joules.
I HOPE THIS WILL HELP YOU....
given mass m=90kg
initial velocity u=6km/h=6000/60x60m/s=1.667m/s
final velocity V =12km/h=12000/60x60 m/s=3.334
using v^2=u^2+2aS
2aS=(3.334)^2-(1.667)^2
aS =11.116-2.779/2
aS=8.337/2
aS =4.1685 m^2/sec.square
therefore,
W=FxDisplacement
W=ma x S. [F=ma,where a=acceleration ]
W=m x(aS)
W=90x4,1685
W=375.165 joules
Hence work done to increase the speed of bicycle by the bicyclists =375.165 joules.
I HOPE THIS WILL HELP YOU....
Similar questions