Question

The mass of a cylindrical container is 7.2 kg when it is full of water and 1200 g when it is empty. It is 50 cm in length. Find it's diameter and it's capacity in litres.
Please answer correctly. I will mark as Brainliest.​

Answer 1

cylindrical container's diameter=42 cm

cylindrical container's diameter=42 cmradius=21cm

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cm

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cmvolume of rise in the level of the water of cylindrical container=volume of rectangular solid

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cmvolume of rise in the level of the water of cylindrical container=volume of rectangular solidΠr

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cmvolume of rise in the level of the water of cylindrical container=volume of rectangular solidΠr 2

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cmvolume of rise in the level of the water of cylindrical container=volume of rectangular solidΠr 2 h=l∗b∗h

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cmvolume of rise in the level of the water of cylindrical container=volume of rectangular solidΠr 2 h=l∗b∗hΠ21

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cmvolume of rise in the level of the water of cylindrical container=volume of rectangular solidΠr 2 h=l∗b∗hΠ21 2

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cmvolume of rise in the level of the water of cylindrical container=volume of rectangular solidΠr 2 h=l∗b∗hΠ21 2 h=22∗14∗10.5

cylindrical container's diameter=42 cmradius=21cm rectangular solid of iron's dimensions =22cm*14cm*10.5cmvolume of rise in the level of the water of cylindrical container=volume of rectangular solidΠr 2 h=l∗b∗hΠ21 2 h=22∗14∗10.5h=2.33

Answer 2

Answer:

$diameter = (7200 + 1200)g = 8400g. \\ = \frac{8400}{2} = 4200g. \\ 4200 \times 50 = 210000. \\ \frac{210000}{2} = 105000 \frac{g}{cm} .$