Question

The mass of a gas that occupies a volume of 612.5 ml at room temperature and pressure (250 c and 1 atm pressure) is 1.1g. The molar mass of the gas is

Answer 1

formula M=dRT/P

M = molar mass (g/mol)

d = density (g/L)

R = Ideal Gas Constant ( ≈ 0.0821) a t m ⋅ L/ m o l ⋅ K )

T = Temperature (In Kelvin)

P = Pressure (atm)

T = 25 ° C + 273.15 = 298.15

V= 612.5 mL . 1000 mL/ 1 L = 0.1625 L

P = 1 ATM

Find density

1.1 g/ 0.1625 L = 1.8

M=dRT/P

= (1.8*0.0821 *298.15)/1

= 44.06

Hence the answer is 44