Physics, asked by roshankumarmahto2004, 3 months ago

The mass of A is two times the mass of B if they move with the same momentum .what is the ratio of the kinetic energy of A to that of B.​

Answers

Answered by Anonymous
1

Answer:

Explanation:

m1​v1​=m2​v2​

v2​v1​​=m1​m2​​

Now, for ratio of kinetic energy, we have

KE2​KE1​​=21​m2​v22​21​m1​v12​​

=(m2​m1​​)(v2​v1​​)2

=(m2​m1​​)(m1​m2​​)2

=m1​m2​​

Answered by neha708884
1

Answer:

Let the mass of the A be 2B and B be B

Momentum are same ° Velocity of A = Velocity of B

Ratio of the kinectic energy of A to that B is,,,,

1/2 mv² ÷ 1/2mv²

= 1/2 × 2B × ÷ 1/2 × B ×

= 2/1 = 2 : 1

therefore,,, answer is 2 : 1

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