Question

The mass of a lift is 500 kg. What will be the tension in its cable ifit moves down with an acceleration
2 m-sec2
1) 4000 N
2) 5000 N
3) 6000N
4) 3000 N
0 1​

Answer 1

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Required answer-:

Let the tension in the cable be T

The equation of motion for the lift is:

T−mg=ma where m=mass of the lift, a= acceleration of the lift)

⇒T=m(g+a)

⇒T=500(10+2)=500×12=6000N.

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Answer 2

Answer:

4000N

Explanation:

forces acting on the lift are

1)Tension on the string upwards

2)Mg downwards

Now according to free body diagram

Net force= Mg-T (cause lift is moving downwards duh)

this Net force equal to Mass of lift times acceleration of lift

=> Mg-T=M*a

=> 5000-T=500×2

=> T= 4000N

Hope it works