Question

The mass of a lift is 500 kg. When it ascends with
an acceleration of 2 m/s2, the tension in the cable
will be
(g = 10 m/s)​

Answer 1

Answer:

Mass of the lift = 500kg

Acceleration = 2m/s²

g = 10m/s

Explanation:

Force 'ma' is in the direction of motion ie. downwards. Also mg is applied in the downward direction . The direction of tension is always along the string and away from the body ie. in upward direction.

So, on balancing the forces

We get an equation

T = mg + ma

T = m( g + a )

T = 500 ( 10 + 2 )

T = 500 ( 12 )

T = 6000 N