Question

The mass of a man standing on the ground is 50kg. The area of each the foot of the man is 0.2 sq.m.
What is the pressure exerted by the man on the ground?​

Answer 1

Answer -

• The pressure exerted by the man on the ground = 1225N/m².

To calculate -

• The pressure exerted by the man on the ground.

Step-by-step explanation -

• Here, the mass of a man standing on the ground and the area of each of his foot is given to us. We have to calculate the pressure exerted by him on the ground.

We know that -

$\bigstar \: \underline{\boxed{\sf Weight \: of \: a \: 1 \:kg \: mass = 9.8N}}$

Here -

• Mass = 50 kg.

Converting mass into newton -

$\rm \leadsto \: 50 \times 9.8 = 490N.$

____________________________

Now, given that -

• The area of each of the foot of the man is 0.2 sq.m.

Therefore -

• Area of his 2 feet = 0.2 × 2 = 0.4 m².

We know that -

$\bigstar \: \underline{\boxed{\sf Pressure = \dfrac{Force}{Area}}}$

Here -

• Force = 490N.
• Area = 0.4 m².

Therefore -

$\tt\longrightarrow \: Pressure = \cancel{\dfrac{490}{0.4}}$

$\tt \longrightarrow \: Pressure = 1225N/m^2$

Hence -

• The pressure exerted by the man on the ground = 1225N/m².

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