the mass of a molecule of CaCo3
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Answered by
3
Mass of Calcium Carbonate = Ca + C +3O
= 40+12+3(16)
= 40+12+48
= 100 g or a.m.u
#Praneeth
= 40+12+3(16)
= 40+12+48
= 100 g or a.m.u
#Praneeth
Answered by
1
100.0869g/mol is the mass of CaCo3
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