The mass of a pebble was 88.4. The original volume of water in the measuring cylinder was 50cm3 and the combined volume of water and pebble was 84cm3 . what is the density of the rock in the pebble?
Answers
Answer:
The volume of the stone is equal to the volume of the water increased in the measuring cylinder.
The volume of the stone is calculated from the formula Volume =Mass/Density.
In this case, the Mass = 12 g and Density = 3gcm
3
.
Volume = 12/3 = 4cm
3
.
The actual volume of liquid in the measuring cylinder is 20cm
3
.
So, the increase in volume will show a new reading of 20cm
3
+4cm
3
=24cm
3
.
Hence, the new reading on the measuring cylinder is 24cm
3
.
Answer:
2.69 g/cm3
Explanation:
As you know, the formula for Density is Mass/Volume.
In the Question, it is stated that the mass of the pebble is 88.4 g. Now to find the volume of that pebble, We have to follow this equation (Combined volume of water and pebble - Original Volume of Water). By This, it mean 84-50=34. So let us substitute the values with the equation. 88.4/34 = 2.69g/cm3.