the mass of a planet is 6×10^24 kg and its diameter is 12.8 ×10^3 km if the value of gravitational constant be 6.7×10^-11 Newton metre square per kg square calculate the value of acceleration due to the gravity on the surface of the planet planet could this be
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140
Given,
Maas of planet = 6*10^24 kg
Radius of planet = 6.4*10^6 m
G = 6.7*10^-11 Nm^2/kg^2
As we know that,
g = (G*m)/r^2
or, g = {(6.7*10^-11)*(6*10^24)}/(6.4*10^6)^2
or g = 9.81 meter per second square
Maas of planet = 6*10^24 kg
Radius of planet = 6.4*10^6 m
G = 6.7*10^-11 Nm^2/kg^2
As we know that,
g = (G*m)/r^2
or, g = {(6.7*10^-11)*(6*10^24)}/(6.4*10^6)^2
or g = 9.81 meter per second square
atul45515pes1iq:
but answer is 9.8 m^2
it is also true
In question the one decimal digit so answer is also in one decimal digit
Answered by
26
9.8 m/s²
Earth
hope it helps
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