Science, asked by atul45515pes1iq, 1 year ago

the mass of a planet is 6×10^24kg and its diameter is 12.8×10^3km. If the value of gravitational constant is 6.7×10^-11 Nm^2/kg^2,claculate thae value of accelaration due to gravity on the surface of the planet. what planet could this be?

Answers

Answered by kumartapas294p0odjm
1
acceleration due to gravity,g= GM/R^2
so here,
6.7×10^-11×6×10^24/(12.8×10^3×10^3)^2=2.45m/s^2
this planet may be jupiter
Similar questions