the mass of a scooter along with its rider is 150kg. the scooter moving at a velocity of 72km/hr is stopped in 10sec after brakes were applied. find the force required by the brakes to stop the scooter.
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Initial velocity(u) = 72 km/hr × 5/18 = 20 m/s
Final velocity (v)= 0 m/s
Time taken to stop the vehicle = 8s
Mass of scooter and Kashvi = 170Kg
We will use the formula F = ma.
a = v - u / t
= 0 - 20/8
= -20/8. Therefore, Retardation =
= 2.5 \: m\ {s}^{ - 2}=2.5m s
−2
F = ma
= 170 × -2.5
425 N ( Answer )
Explanation:
First convert the km/hr to m/s.
Negative acceleration = Retardation
Newton's Second Law Formula:-
F = ma
where,
m = mass of the body
a = acceleration produced by the body
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Answer:
force experienced is 300N
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