Question

The mass of a simple pendulum Bob is 100 gm. The length of the pendulum is 1m. The Bob is drawn aside from the equilibrium position so that the string makes an angle of 60 degrees with the verticle and let go. The kinetic energy of the bob while crossing it's equilibrium position will be ​

Answer 1

Answer:

Formula:

h=l (1-cos¤)

V=root of 2gl (1-cos¤)

Answer 2

Answer:

Formula:

h=l (1-cos¤)

V=root of 2gl (1-cos¤)

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