Question

The mass of a single barium atom is 2.28×10-22 grams. How many barium atoms would there be in 306 milligrams of barium?

Answer 1

Given:

Mass of single barium atom = 2.28×10⁻²² grams

Mass of barium = 306 milligrams = 0.396 grams

To find:

Number of atoms in 306 milligrams of barium

Calculation:

We know the formula

Number of atoms = Total mass / Mass of single atom

                             = 0.306 / 2.28×10⁻²²

                             = 0.134×10²²

                             = 13.4×10²⁰ atoms

Number of atoms in 306 milligrams of barium is 13.4×10²⁰ atoms

Answer 2

Answer:

1.34 x 10^21

Step-by-step explanation:

1. Convert 306 milligrams to grams (conversions: 1 mg = 10^-3 g)

$306mg * \frac{10^-3g}{1 mg}$ = 0.306g

2. Multiply 0.306g and 2.28 x 10^-22g to get atoms

$0.306g *\frac{1 atom}{2.28*10^-22g}$ = 1.342105263 x 10^21 = 1.34 x 10^21 atoms