Question

The mass of a stone is 50g. To determine its density water is taken in a measuring cylinder whose initial level is 20ml. When the stone is immersed in the measuring cylinder the water level rises to 35ml. Find the density of the stone.

Answer 1

Answer:

density=33333.33 kg/m^3

Explanation:

volume of water displace=volume of stone

volume of stone=35-20

volume of stone=15ml

as we know,

1m^3=10^6 ml

15ml=15/10^6 m^3

density=mass/volume

. =(50/100)*(10^6/15)

=50*10000/15

=10^5/3

=33333.33 kg/m^3

Answer 2

Answer:

Solution:

Mass of the stone = 50g

As the rise in the water level gives a measure of the volume of the stone, therefore the volume

of the stone = 20ml = 20cm cube

( :. 1 mL = 1 cm cube )

therefore

$p = \frac{m}{v} \\ = \frac{50}{20} = 2.5g {}^{3}$

the density of the stone is 2.5cm cube