The mass of a sulphur atom in avo grams is
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your answer is
Explanation:
Gram-atomic mass of sulphur = 32=32 g
Mass of one sulphur atom =\dfrac { Gram-atomic\, mass}{ 6.02 \times 10^{23}}=
6.02×10
23
Gram−atomicmass
=\dfrac {32}{6.02 \times 10^{23}}= 33 \times 10^{-23} g=
6.02×10
23
32
= 33×10
−23
g
Formula of carbon dioxide = CO_2=CO
2
Molecular mass of = CO_2 =12 +2 \times 16 = 44=CO
2
=12+2×16=44
Gram-molecular mass of CO_2 = 44 gCO
2
=44g
Mass of one molecule of CO_2 = \dfrac { Gram-atomic\, mass}{ 6.02 \times 10^{23}}CO
2
=
6.02×10
23
Gram−atomicmass
=\dfrac { 44}{ 6.02 \times 10^{23}}= 7.308 \times 10^{-23}\, g=
6.02×10
23
44
=7.308×10
−23
g
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