Question

The mass of ammonia in grams produced when 2.8 kg of dinitrogen quantitatively reacts with 1 kg of dihydrogen is _____​

Answer 1

The mass of ammonia in grams produced when 2.8 k is g of dinitrogen quantitatively reacts with 1 kg of dihydrogen is 3400 grams.

Given:

2.8 kg of dinitrogen quantitatively reacts with 1 kg of dihydrogen.

To Find:

The mass of ammonia in grams is produced when 2.8 kg of dinitrogen quantitatively reacts with 1 kg of dihydrogen.

Solution:

To find the mass of ammonia in grams produced when 2.8 kg of dinitrogen quantitatively reacts with 1 kg of dihydrogen we will follow the following steps:

As we know,

N2 + 3H2 → 2NH3

2800 g of dinitrogen reacts with 1000g of dihydrogen.

Number of moles of dinitrogen = $\frac{2800}{28}$= 100

Number of moles of dihydrogen = $\frac{2800}{28}$ =500

1 mole of N2 requires 3 moles of H2.

So,

N2 is a limiting reagent because dihydrogen is in excess as only 300 moles of dihydrogen can react with 100 moles of dinitrogen and 200 moles of hydrogen are in excess.

So, N2 will decide the product formation.

According to the reaction,

1 mole of N2 gives 2 moles of ammonia.

100 moles of N2 will give 200 moles of NH3.

The molecular mass or mass of 1 mole of ammonia is 17 grams.

Mass of 200 moles of ammonia = 200×17 = 3400gram.

Henceforth, the mass of ammonia in grams produced when 2.8 k is g of dinitrogen quantitatively reacts with 1 kg of dihydrogen is 3400 grams.