Question

The mass of an atom of sodium is 23 u. Calculate the
number of sodium atoms in 1 mg.
Take 1 u = 1.66 x 10^-27 kg.

the answer is 2.62×10^19
I need the process , to solve it​

Answer 1

$\Large\bf\underline{\underline{ Given:-}}$

• The mass of an atom of sodium is 23 $\mu$

$\Large\bf\underline{\underline{ To \: find :-}}$

• the number of sodium atoms in 1 mg

$\Large\bf\underline{\underline{ Formula \: used :-}}$

$\boxed{ \bf1 \mu \: = 1.66 \times {10}^{ - 27} kg}$

$\boxed{ \bf \: 1 mg = \frac{1}{1000000} kg}$

$\Large\bf\underline{\underline{ Answer :-}}$

$\bf mass \: of \: sodium \: atom = 23 \mu$

$\bf \: mass \: of \: Na \: = 23 \times 1.66 \times {10}^{ - 27}$

$\bf \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 3.818 \times {10}^{ - 26} kg$

$\bf \: no. \: of \: Na \: atoms \: = \frac{0.000001 }{3.818 \times {10}^{ - 26} }$

$\bf\red{ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 2.619 \times {10}^{19} } \: \:$

$\rule{15cm}{0.02cm}$

Answer 2

Answer:

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