Question

The mass of an electron is 9.11x10^-31 kg and is its kinetic energy is 3 x 10^-25 j calculate its wavelength

Answer 1

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8.96 × 10⁻⁷ m = 896 nm

KE = ½ mv²

v= $\sqrt[]{\frac{KE}{m} }$

= $\sqrt[]{\frac{3x10^-^2^5}{9x10^-^3^1} }$

= $\sqrt[]{\frac{10^6}{3} }$ = 811.58 m/s

now, by de- Broglie wavelength

λ = $\frac{h}{mv}$

λ = $\frac{6.6x10^-^3^4}{9x10^-^3^1x811.58}$ ≈ 896 nm

Answer 2

Answer:

Explanation:

We know,

De Broglie wavelength=h/p,where h is Planck's constant and p is momentum of electron.

Now,Kinetic energy=(p^2)/(2m),where m is mass,p is momentum.

p^2=2mKE=

2*9.1*10^-31*3*10^-25=54.6*10^-66

So,p=7.39*10^-33

Hence, wavelength=(6.63*10^-34)/(7.39*10^-33)=

8.97*10^-2 m.