Question

the mass of an elevator lift is 500 kilograms calculate the tension in the cable of the elevator when the elevator is first stationary second ascending with an acceleration of 2.0 M per second square third descending with the same acceleration G is equal to 9.8 Newton per kilogram

Answer 1

In the first case the tension is

T=mg

=500(9.8)

=4900N

In the second case,

it is accelerating with 2 m/s^2

T=mg-ma

=4900-(500)(2)

=3900N

In the third case,

T=mg-ma

=4900-(-2)(500)

5900N

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Answer 2

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