Question

The mass of an imaginary planet is 3 times the mass of the earth.Its diameter is 25600Km and the earth's diameter ia 12800 km.Find the value of the acceleration due to gravity at the surface of the planet.

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Answer 1

$m = 3 \times 5.972 \times {10}^{24} kg \\ m = 17.916 \times {10}^{24}kg \\ \\ r = \frac{d}{2} \\ r = \frac{25600000}{2} = 12800000 \: or \\ r = 1.28 \times {10}^{7}m \\ \\ g = \frac{g.c \times m}{ {r}^{2} } \\ g = \frac{6.674 \times {10}^{ - 11} \times 17.916 \times {10}^{24} }{{(1.28 \times {10}^{7} )}^{2} } \\ g = \frac{119.571 \times {10}^{13} }{1.638 \times {10}^{14} } \\ g = 73 \times {10}^{ - 1} \\ g = 7.3m/{s}^{2}$

Answer 2

above answer is correct