The mass of an iron ball is 800 g and its volume is 100 cm^3. The density of iron ball in SI unit is.
8 g/cm^3
80 g/cm^3
800 kg/m^3
8000 kg/m^3
Answers
Answer:
8000 Kg/m³
Explanation:
Given :-
Mass of an iron ball = 800g
Volume of the iron ball = 100cm³
- 100/1000 m³
- 0.1 m³
To find :-
Density of the iron ball in S.I unit.
Solution :-
➤ Density = Mass ÷ Volume
⇒ Density = 800 ÷ 0.1
⇒ Density = 8000 Kg/m³
∴ Density of iron ball is 8000 Kg/m³.
Answer:
8000kg/m³
Explanation:
Given,
Mass of an iron ball 800g
And it's volume 100cm³
Since, density of an object is the mass per volume.
Therefore, Density of the iron ball is given by,
⇒ρ = m/v
Where,
- m(mass) = 800g
- v(volume) = 100cm³
So, the density is -
⇒ ρ = 800/100
⇒ ρ = 8g/cm³
⇒ ρ = 8000kg/m³
Hence, the density of the iron ball is 8000kg/m³
_____________________
Density - A measurement of mass per units of volume.
S. I. unit of density - kilogram per centimetre cube.
Formula used :
- ρ = m/v
Where, ‘m’ denotes the mass and ‘v’ denotes the volume of the object.