Physics, asked by yashk5947, 4 hours ago

The mass of an iron ball is 800 g and its volume is 100 cm^3. The density of iron ball in SI unit is.



8 g/cm^3

80 g/cm^3

800 kg/m^3

8000 kg/m^3​

Answers

Answered by CopyThat
7

Answer:

8000 Kg/m³

Explanation:

Given :-

Mass of an iron ball = 800g

Volume of the iron ball = 100cm³

  • 100/1000 m³
  • 0.1 m³

To find :-

Density of the iron ball in S.I unit.

Solution :-

➤ Density = Mass ÷ Volume

⇒ Density = 800 ÷ 0.1

⇒ Density = 8000 Kg/m³

Density of iron ball is 8000 Kg/m³.

Answered by ImperialGladiator
27

Answer:

8000kg/m³

Explanation:

Given,

Mass of an iron ball 800g

And it's volume 100cm³

Since, density of an object is the mass per volume.

Therefore, Density of the iron ball is given by,

⇒ρ = m/v

Where,

  • m(mass) = 800g
  • v(volume) = 100cm³

So, the density is -

⇒ ρ = 800/100

⇒ ρ = 8g/cm³

⇒ ρ = 8000kg/m³

Hence, the density of the iron ball is 8000kg/

_____________________

Density - A measurement of mass per units of volume.

S. I. unit of density - kilogram per centimetre cube.

Formula used :

  • ρ = m/v

Where, m denotes the mass and v denotes the volume of the object.

Similar questions