The mass of an iron cube having an edge length 1.5 cm is 50g. Find its density.
Answers
Answered by
36
Density=Mass/Volume
For the iron cube,
Mass=50g
Volume= 1.5³ = 3.375 cm³
So,
Density= Mass/Volume
=50/3.375
=14.81481
∴Density≈14.81 g/cm³
Thus, density of the iron cube is 14.81 g/cm³
For the iron cube,
Mass=50g
Volume= 1.5³ = 3.375 cm³
So,
Density= Mass/Volume
=50/3.375
=14.81481
∴Density≈14.81 g/cm³
Thus, density of the iron cube is 14.81 g/cm³
QGP:
Hope it helps
Answered by
19
volume of the cube = 1.5³ = 3.375 cm³
density = mass / volume
density = 50 / 3.375
density of the iron cube = 14.8 gm / cm³
density = mass / volume
density = 50 / 3.375
density of the iron cube = 14.8 gm / cm³
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