Question

The mass of an iron cube having an edge length 1.8cm is 70g. Find its density

Answer 1

volume =a^3
=1.8^3
=0.054
mass=70g
density=m/v
=(70/0.054) gcm-3
=1296.296 gcm-3

Answer 2

Mass=density*volume
Volume =1.8 cube
=5.832
70/5.832=density
=12.002