Question

the mass of an iron cube having edge 1.8 cm is 70 g. finds its density

Answer 1

Density = Mass / Volume

Here,
Mass ( m) = 70g
Volume = (1.8)³ = 5.832 cm³ .

Density = 70 / 5.832 = 12.00 g/cm³

Answer 2

Heya!

Volume of iron cube = (1.8)^3 = 5.83 cm^3

Mass = 70 gm

Then,

Density = Mass / Volume

= 70/5.83

=12 gm cm^-3

Hope it helps u.