the mass of an iron rod is 80 gram and its magnetic moment is 10 ampere metre square if the density of an iron is 8 gram per CC then the value of intensity of magnetization will be
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Answer:
The answer is 10^6 A/m.
Explanation:
The formula to calculate the intensity of magnetization is :
M = Magnetic moment/volume = M / V
The S.I unit of M is A/m
Given data:
Mass (m) = 80 g = 80 / 1000 = 0.08 kg
Magnetic moment = 10 Am2
Density = 8 g / cm3 = 8000 Kg/m3
p = m/V
V =m /p
V = 0.08/ 8000 = 1x 10^-5
M = M / V
= 10 / 1x 10 ^ -5
M = 10 x 10^5 A/m = 10^6 A/m
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