Question

the mass of an iron rod is 80 gram and its magnetic moment is 10 ampere metre square if the density of an iron is 8 gram per CC then the value of intensity of magnetization will be

Answer 1

Answer:

The answer is 10^6 A/m.

Explanation:

The formula to calculate the intensity of magnetization is :

M = Magnetic moment/volume = M / V

The S.I unit of M is A/m

Given data:

Mass (m) = 80 g = 80 / 1000 = 0.08 kg

Magnetic moment = 10 Am2

Density = 8 g / cm3 = 8000 Kg/m3

p = m/V

V =m /p

V = 0.08/ 8000 = 1x 10^-5

M =  M / V

   = 10 / 1x 10 ^ -5

M = 10 x 10^5 A/m = 10^6 A/m