the mass of an object is 105 g .When it is immersed into a measuring cylinder,the water level rises from 25 ml to 30 ml mark .Find the value of the object and its density in kg/m³
Answers
Answered by
6
Answer:
Given, M = 115g
V
1
= 20 ml, V
2
= 30 ml
Volume of lead piece V = V
2
−V
1
= 30 ml - 20 ml
= 10 ml or 10 cm
3
[∵1ml=1cm
3
]
Answered by
2
Answer:
Given, M = 115g
V
1
= 20 ml, V
2
= 30 ml
Volume of lead piece V = V
2
−V
1
= 30 ml - 20 ml
= 10 ml or 10 cm
3
[∵1ml=1cm
3
]
Answered by
1
Answer:
Given, M = 115g
V
1
= 20 ml, V
2
= 30 ml
Volume of lead piece V = V
2
−V
1
= 30 ml - 20 ml
= 10 ml or 10 cm
3
[∵1ml=1cm
3
]
Answered by
1
Answer:
Given, M = 115g
V
1
= 20 ml, V
2
= 30 ml
Volume of lead piece V = V
2
−V
1
= 30 ml - 20 ml
= 10 ml or 10 cm
3
[∵1ml=1cm
3
]
Answered by
1
Answer:
Given, M = 115g
V
1
= 20 ml, V
2
= 30 ml
Volume of lead piece V = V
2
−V
1
= 30 ml - 20 ml
= 10 ml or 10 cm
3
[∵1ml=1cm
3
]
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