Question

the mass of an object is 54.22+0.01 kg the % error in the measurement of masa

Answer 1

(0.01/54.22)×100=0.018%

Answer 2

Answer:

The percentage error is $0.018$%.

Explanation:

It is given that the mass of an object is $54.22+0.01$ kg.

We need to determine the percentage error.

From the given mass, it can be evaluated that the error in the given statement is $0.01$, mass is $54.22$.

So, the percentage error will be calculated as:

Error = $\frac{0.01}{54.22} *100$

Solving this, we get

Error is $0.018$%.

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